Web28 Aug 2024 · Sum = 1215 HCF = 81 Concept used: If we divide two number by their HCF then the quotient will be co - Prime i.e. prime to each other. Calculation: Let the numbers … Web18 Oct 2024 · Given: Sum of two numbers = 1215 H.C.F of the numbers = 81. To find: Possible pairs of numbers Let: The numbers be X and Y Solution: According to the given question, H.C.F of the numbers = 81. It means both the numbers must be multiples of 81
21 1 If sum of two numbers is 1215 and their HCF is 81, then the ...
WebQuestion : If the sum of two numbers is 1215 and their HCF is 81, then the possible number of pairs of such numbers are a) 2 b) 3 c) 4 d) 5 Doubt by Vanshika Solution : HCF of both the numbers is 81, it means that both are divisible by 81 or we can also say that both are the multiples of 81. Correct? Let us consider the two numbers by P and Q Now WebHCF =27=3×3×3 common prime factors of the two numbers are 3×3×3 216÷3=72÷3=24÷3=8 8=1+7 , 8=3+5 , (1,7) and (3,5) are the two sets of uncommon factors . two numbers may be ( 27×1, 27×7 ) or ( 27×3 , 27×5 ) ( 27 , 189 ) or ( 81 , 135 ) 1 Argyris Sofroniou Author has 439 answers and 736.2K answer views 3 y 27x+27y=216 => x+y=8 fact checking clubs in universities
If sum of two numbers is 1215 and their HCF is 81, then the …
Web8 Sep 2024 · if sum of two numbers is 1215 and their HCF is 81, then the possible numbers of the pairs of such n dev classes Dehradun 27.6K subscribers 221 Dislike Share 5,597 views Streamed live... WebIf sum of two numbers is 1215 and their HCF is 81 then , How many such pairs of numbers are possible? Solution Find the possible number of pairs Since HCF of both numbers is 81 … Web1 Dec 2024 · HCF of two numbers = 27 Let the numbers be 27x and 27y where x and y are prime to each other. According to the question, 27x + 27y = 216 27 (x + y) = 216 x + y = 216 27 216 27 =8 Possible pairs of x and y = (1, 7) and (3, 5) Numbers = (27, 189) and (81, 135) Other Questions 1. does the iphone 13 use lightning cable