WebApply the difference operator Δ g ( n) = g ( n + 1) − g ( n) to f repeatedly. Then apply it to a polynomial and compare the results. [ Edit in response to the comment:] An integral can be thought of as a limit of a sum. WebMay 17, 2024 · g(n)=g(n-1)*6.1 find an explicit formula for g(n) See answers Advertisement Advertisement meandmycousinmagic meandmycousinmagic Answer: 2.7(6.1)^(n-1) Step-by-step explanation: [(6.1)^(n-1)]*g(1) =[(6.1)^(n-1)]*2.7 =2.7*(6.1)^(n-1) Advertisement Advertisement LammettHash LammettHash
Converting recursive & explicit forms of arithmetic sequences
WebHere is an explicit formula of 3, 5, 7, ... a (n)=3+2 (n-1) a(n)=3+2(n−1) This formula allows us to simply plug in the number of the term we are interested in to get the value of that term. In order to find the fifth term, for example, we need … WebNov 14, 2024 · = + (n - 1 )d where is the first term and d the common difference d = 99 - 90 = 90 - 81 = 81 - 72 = 9 and = 72 = 72 + 9 (n - 1) = 72 + 9n - 9 = 9n + 63 ← explicit formula Advertisement jiaojason2024 Answer: 9n + 63 Step-by … cvs acne control gel
Find an explicit formula for sequence ao; 01 02, that… - SolvedLib
WebAn explicit formula for the sequence . 14,5,-4,-13... given by Imran is g(n)=14-9(n-1) and by Aubrey is g(n)=14-9n. We have to determine who is right. g(n)= 14-9n. g(1)=14-9 = 5. Hence, formula given by Aubrey is wrong. g(n)=14-9(n-1) g(1)=14-9(0)=14. g(2)=14-9(1)=5. g(3)=14-9(2)= -4. g(4)=14-9(3)= -13. Hence, formula given by Imran is correct WebDec 4, 2024 · Wang Lei said the formula is g (n)=30\cdot5^ {\large {n-1}}g (n)=30⋅5 n−1 g, left parenthesis, n, right parenthesis, equals, 30, dot, 5, start superscript, n, minus, 1, end superscript, and Amira said the formula is g (n)=6\cdot5^ {\large {n}}g (n)=6⋅5 n WebExplicit formulas for geometric sequences. Wang Lei and Amira were asked to find an explicit formula for the sequence 30\,,\,150\,,\,750\,,\,3750,... 30, 150, 750, 3750,..., where the first term should be g (1) g(1). Wang Lei said the formula is g (n)=30\cdot5^ { {n-1}} g(n) = 30⋅ 5n−1, and. Amira said the formula is g (n)=6\cdot5^ { {n}} g ... cvs adams and magnolia riverside ca